Base | Representation |
---|---|
bin | 10010111001011001101010… |
… | …01100001101001001101001 |
3 | 12110010120221120002220001102 |
4 | 21130230311030031021221 |
5 | 20421313011422341331 |
6 | 224213544401531145 |
7 | 11516141141246366 |
oct | 1134546514151151 |
9 | 173116846086042 |
10 | 41554700980841 |
11 | 12271282413a44 |
12 | 47b16b5343ab5 |
13 | 1a2578c666149 |
14 | a3938893b46d |
15 | 4c0dee4e94cb |
hex | 25cb3530d269 |
41554700980841 has 2 divisors, whose sum is σ = 41554700980842. Its totient is φ = 41554700980840.
The previous prime is 41554700980721. The next prime is 41554700980883. The reversal of 41554700980841 is 14808900745514.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22881680910400 + 18673020070441 = 4783480^2 + 4321229^2 .
It is a cyclic number.
It is not a de Polignac number, because 41554700980841 - 214 = 41554700964457 is a prime.
It is not a weakly prime, because it can be changed into another prime (41554700983841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20777350490420 + 20777350490421.
It is an arithmetic number, because the mean of its divisors is an integer number (20777350490421).
Almost surely, 241554700980841 is an apocalyptic number.
It is an amenable number.
41554700980841 is a deficient number, since it is larger than the sum of its proper divisors (1).
41554700980841 is an equidigital number, since it uses as much as digits as its factorization.
41554700980841 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6451200, while the sum is 56.
The spelling of 41554700980841 in words is "forty-one trillion, five hundred fifty-four billion, seven hundred million, nine hundred eighty thousand, eight hundred forty-one".
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