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41613354423401 = 61176476802183
BaseRepresentation
bin10010111011000110111010…
…01101010101010001101001
312110100012100012220111020212
421131203131031111101221
520423243122213022101
6224300524444430505
711523315500264555
oct1135433515252151
9173305305814225
1041613354423401
1112294140794512
124800b44248435
131a2b179136b87
14a3c150630865
154c26d39121bb
hex25d8dd355469

41613354423401 has 4 divisors (see below), whose sum is σ = 41613367343232. Its totient is φ = 41613341503572.

The previous prime is 41613354423341. The next prime is 41613354423451. The reversal of 41613354423401 is 10432445331614.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 41613354423401 - 222 = 41613350229097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41613354423451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2716556 + ... + 9518738.

It is an arithmetic number, because the mean of its divisors is an integer number (10403341835808).

Almost surely, 241613354423401 is an apocalyptic number.

It is an amenable number.

41613354423401 is a deficient number, since it is larger than the sum of its proper divisors (12919831).

41613354423401 is an equidigital number, since it uses as much as digits as its factorization.

41613354423401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12919830.

The product of its (nonzero) digits is 414720, while the sum is 41.

The spelling of 41613354423401 in words is "forty-one trillion, six hundred thirteen billion, three hundred fifty-four million, four hundred twenty-three thousand, four hundred one".

Divisors: 1 6117647 6802183 41613354423401