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416244054313 is a prime number
BaseRepresentation
bin1100000111010100001…
…01000011100100101001
31110210101202121211101001
412003222011003210221
523304431434214223
6515115254355001
742033626040643
oct6035205034451
91423352554331
10416244054313
11150589a0a87a
126880735ba61
1330336b348b9
1416209703893
15ac62a4b9ad
hex60ea143929

416244054313 has 2 divisors, whose sum is σ = 416244054314. Its totient is φ = 416244054312.

The previous prime is 416244054229. The next prime is 416244054367. The reversal of 416244054313 is 313450442614.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 269373456144 + 146870598169 = 519012^2 + 383237^2 .

It is a cyclic number.

It is not a de Polignac number, because 416244054313 - 213 = 416244046121 is a prime.

It is a super-2 number, since 2×4162440543132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (416244054913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 208122027156 + 208122027157.

It is an arithmetic number, because the mean of its divisors is an integer number (208122027157).

Almost surely, 2416244054313 is an apocalyptic number.

It is an amenable number.

416244054313 is a deficient number, since it is larger than the sum of its proper divisors (1).

416244054313 is an equidigital number, since it uses as much as digits as its factorization.

416244054313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 416244054313 its reverse (313450442614), we get a palindrome (729694496927).

The spelling of 416244054313 in words is "four hundred sixteen billion, two hundred forty-four million, fifty-four thousand, three hundred thirteen".