Base | Representation |
---|---|
bin | 1100001100110010010… |
… | …10100100010110010001 |
3 | 1111001222110222010220012 |
4 | 12012121022210112101 |
5 | 23331440431341311 |
6 | 520322550324305 |
7 | 42166465030523 |
oct | 6063112442621 |
9 | 1431873863805 |
10 | 419181512081 |
11 | 151857043322 |
12 | 692a7059695 |
13 | 306b458bca7 |
14 | 164078a9a13 |
15 | ad8588978b |
hex | 61992a4591 |
419181512081 has 2 divisors, whose sum is σ = 419181512082. Its totient is φ = 419181512080.
The previous prime is 419181512047. The next prime is 419181512107. The reversal of 419181512081 is 180215181914.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 392257953025 + 26923559056 = 626305^2 + 164084^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-419181512081 is a prime.
It is a super-2 number, since 2×4191815120812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (419181512011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 209590756040 + 209590756041.
It is an arithmetic number, because the mean of its divisors is an integer number (209590756041).
Almost surely, 2419181512081 is an apocalyptic number.
It is an amenable number.
419181512081 is a deficient number, since it is larger than the sum of its proper divisors (1).
419181512081 is an equidigital number, since it uses as much as digits as its factorization.
419181512081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 41.
Adding to 419181512081 its reverse (180215181914), we get a palindrome (599396693995).
The spelling of 419181512081 in words is "four hundred nineteen billion, one hundred eighty-one million, five hundred twelve thousand, eighty-one".
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