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419502300081 = 3139834100027
BaseRepresentation
bin1100001101011000100…
…10010001101110110001
31111002210211120212022020
412012230102101232301
523333120042100311
6520414450102053
742210441500514
oct6065422215661
91432724525266
10419502300081
11151a01126077
126937657a929
1330735b87a87
1416438330d7b
15ada3b02c06
hex61ac491bb1

419502300081 has 4 divisors (see below), whose sum is σ = 559336400112. Its totient is φ = 279668200052.

The previous prime is 419502300047. The next prime is 419502300083. The reversal of 419502300081 is 180003205914.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 419502300081 - 215 = 419502267313 is a prime.

It is a super-2 number, since 2×4195023000812 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (419502300083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69917050011 + ... + 69917050016.

It is an arithmetic number, because the mean of its divisors is an integer number (139834100028).

Almost surely, 2419502300081 is an apocalyptic number.

It is an amenable number.

419502300081 is a deficient number, since it is larger than the sum of its proper divisors (139834100031).

419502300081 is a wasteful number, since it uses less digits than its factorization.

419502300081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139834100030.

The product of its (nonzero) digits is 8640, while the sum is 33.

Adding to 419502300081 its reverse (180003205914), we get a palindrome (599505505995).

The spelling of 419502300081 in words is "four hundred nineteen billion, five hundred two million, three hundred thousand, eighty-one".

Divisors: 1 3 139834100027 419502300081