4200112113 has 4 divisors (see below), whose sum is σ = 5600149488. Its totient is φ = 2800074740.

The previous prime is 4200112099. The next prime is 4200112141. The reversal of 4200112113 is 3112110024.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4200112113 - 2¹⁰ = 4200111089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4200112092 and 4200112101.

It is not an unprimeable number, because it can be changed into a prime (4200112153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 700018683 + ... + 700018688.

It is an arithmetic number, because the mean of its divisors is an integer number (1400037372).

Almost surely, 2^4200112113 is an apocalyptic number.

It is an amenable number.

4200112113 is a deficient number, since it is larger than the sum of its proper divisors (1400037375).

4200112113 is a wasteful number, since it uses less digits than its factorization.

4200112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1400037374.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 4200112113 is about 64808.2719488801. The cubic root of 4200112113 is about 1613.4430019544.

Adding to 4200112113 its reverse (3112110024), we get a palindrome (7312222137).

The spelling of 4200112113 in words is "four billion, two hundred million, one hundred twelve thousand, one hundred thirteen".