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420134322121 = 1511278050511
BaseRepresentation
bin1100001110100011111…
…01001111111111001001
31111011102212211220112221
412013101331033333021
523340413341301441
6521001304334041
742232214546413
oct6072175177711
91434385756487
10420134322121
111521a5965638
1269512174321
1330806ab5b07
14164982519b3
15adde3488d1
hex61d1f4ffc9

420134322121 has 4 divisors (see below), whose sum is σ = 420412374144. Its totient is φ = 419856270100.

The previous prime is 420134322119. The next prime is 420134322131. The reversal of 420134322121 is 121223431024.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 420134322121 - 21 = 420134322119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (420134322131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139023745 + ... + 139026766.

It is an arithmetic number, because the mean of its divisors is an integer number (105103093536).

Almost surely, 2420134322121 is an apocalyptic number.

It is an amenable number.

420134322121 is a deficient number, since it is larger than the sum of its proper divisors (278052023).

420134322121 is a wasteful number, since it uses less digits than its factorization.

420134322121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278052022.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 420134322121 its reverse (121223431024), we get a palindrome (541357753145).

The spelling of 420134322121 in words is "four hundred twenty billion, one hundred thirty-four million, three hundred twenty-two thousand, one hundred twenty-one".

Divisors: 1 1511 278050511 420134322121