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4202034003121 is a prime number
BaseRepresentation
bin111101001001011100101…
…111100111110010110001
3112212201011222022110011111
4331021130233213302301
51022321231201044441
612534215431513321
7612405214462303
oct75113457476261
915781158273144
104202034003121
111380088714489
1257a470828841
13246333639046
1410754560b973
1574487cac081
hex3d25cbe7cb1

4202034003121 has 2 divisors, whose sum is σ = 4202034003122. Its totient is φ = 4202034003120.

The previous prime is 4202034003103. The next prime is 4202034003149. The reversal of 4202034003121 is 1213004302024.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4200700292721 + 1333710400 = 2049561^2 + 36520^2 .

It is a cyclic number.

It is not a de Polignac number, because 4202034003121 - 215 = 4202033970353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4202034003092 and 4202034003101.

It is not a weakly prime, because it can be changed into another prime (4203034003121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2101017001560 + 2101017001561.

It is an arithmetic number, because the mean of its divisors is an integer number (2101017001561).

Almost surely, 24202034003121 is an apocalyptic number.

It is an amenable number.

4202034003121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4202034003121 is an equidigital number, since it uses as much as digits as its factorization.

4202034003121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 4202034003121 its reverse (1213004302024), we get a palindrome (5415038305145).

The spelling of 4202034003121 in words is "four trillion, two hundred two billion, thirty-four million, three thousand, one hundred twenty-one".