Base | Representation |
---|---|
bin | 100111001001010010… |
… | …000010100110100011 |
3 | 11000111020222022200020 |
4 | 213021102002212203 |
5 | 1142040100432311 |
6 | 31150432124523 |
7 | 3015404114121 |
oct | 471122024643 |
9 | 130436868606 |
10 | 42031655331 |
11 | 16909856836 |
12 | 8190396743 |
13 | 3c6ac61193 |
14 | 206a346911 |
15 | 116004dc06 |
hex | 9c94829a3 |
42031655331 has 4 divisors (see below), whose sum is σ = 56042207112. Its totient is φ = 28021103552.
The previous prime is 42031655293. The next prime is 42031655357. The reversal of 42031655331 is 13355613024.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 42031655331 - 225 = 41998100899 is a prime.
It is a super-3 number, since 3×420316553313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 42031655292 and 42031655301.
It is not an unprimeable number, because it can be changed into a prime (42031655431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7005275886 + ... + 7005275891.
It is an arithmetic number, because the mean of its divisors is an integer number (14010551778).
Almost surely, 242031655331 is an apocalyptic number.
42031655331 is a deficient number, since it is larger than the sum of its proper divisors (14010551781).
42031655331 is a wasteful number, since it uses less digits than its factorization.
42031655331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14010551780.
The product of its (nonzero) digits is 32400, while the sum is 33.
The spelling of 42031655331 in words is "forty-two billion, thirty-one million, six hundred fifty-five thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •