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42040424131 is a prime number
BaseRepresentation
bin100111001001110011…
…011111011011000011
311000111212110211012121
4213021303133123003
51142044322033011
631151344105111
73015541465126
oct471163373303
9130455424177
1042040424131
11169137a5982
128193305197
133c6ca11514
14206b58a3bd
151160bd1e71
hex9c9cdf6c3

42040424131 has 2 divisors, whose sum is σ = 42040424132. Its totient is φ = 42040424130.

The previous prime is 42040424117. The next prime is 42040424137. The reversal of 42040424131 is 13142404024.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42040424131 - 213 = 42040415939 is a prime.

It is a super-2 number, since 2×420404241312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42040424096 and 42040424105.

It is not a weakly prime, because it can be changed into another prime (42040424137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21020212065 + 21020212066.

It is an arithmetic number, because the mean of its divisors is an integer number (21020212066).

Almost surely, 242040424131 is an apocalyptic number.

42040424131 is a deficient number, since it is larger than the sum of its proper divisors (1).

42040424131 is an equidigital number, since it uses as much as digits as its factorization.

42040424131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 42040424131 its reverse (13142404024), we get a palindrome (55182828155).

The spelling of 42040424131 in words is "forty-two billion, forty million, four hundred twenty-four thousand, one hundred thirty-one".