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42100113044131 is a prime number
BaseRepresentation
bin10011001001010001100100…
…10010000111001010100011
312112001201202021010102220221
421210220302102013022203
521004232012414403011
6225312305215143511
711603430022301032
oct1144506222071243
9175051667112827
1042100113044131
11124616152a175a
12487b34a814b97
131a6503cb9b38c
14a57929014719
154d01c1d13971
hex264a324872a3

42100113044131 has 2 divisors, whose sum is σ = 42100113044132. Its totient is φ = 42100113044130.

The previous prime is 42100113044123. The next prime is 42100113044153. The reversal of 42100113044131 is 13144031100124.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 42100113044131 - 23 = 42100113044123 is a prime.

It is a super-2 number, since 2×421001130441312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42100113044096 and 42100113044105.

It is not a weakly prime, because it can be changed into another prime (42100113044161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21050056522065 + 21050056522066.

It is an arithmetic number, because the mean of its divisors is an integer number (21050056522066).

Almost surely, 242100113044131 is an apocalyptic number.

42100113044131 is a deficient number, since it is larger than the sum of its proper divisors (1).

42100113044131 is an equidigital number, since it uses as much as digits as its factorization.

42100113044131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 42100113044131 its reverse (13144031100124), we get a palindrome (55244144144255).

The spelling of 42100113044131 in words is "forty-two trillion, one hundred billion, one hundred thirteen million, forty-four thousand, one hundred thirty-one".