Base | Representation |
---|---|
bin | 1100010000011110110… |
… | …10100010110110101001 |
3 | 1111021002202000200121211 |
4 | 12020033122202312221 |
5 | 23400021321134003 |
6 | 521251500233121 |
7 | 42266604634552 |
oct | 6101732426651 |
9 | 1437082020554 |
10 | 421165411753 |
11 | 152684993529 |
12 | 6975b53b7a1 |
13 | 3093c5b9c18 |
14 | 16555173329 |
15 | ae4eb1b96d |
hex | 620f6a2da9 |
421165411753 has 2 divisors, whose sum is σ = 421165411754. Its totient is φ = 421165411752.
The previous prime is 421165411721. The next prime is 421165411811. The reversal of 421165411753 is 357114561124.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 417869159184 + 3296252569 = 646428^2 + 57413^2 .
It is a cyclic number.
It is not a de Polignac number, because 421165411753 - 25 = 421165411721 is a prime.
It is not a weakly prime, because it can be changed into another prime (421165411253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210582705876 + 210582705877.
It is an arithmetic number, because the mean of its divisors is an integer number (210582705877).
Almost surely, 2421165411753 is an apocalyptic number.
It is an amenable number.
421165411753 is a deficient number, since it is larger than the sum of its proper divisors (1).
421165411753 is an equidigital number, since it uses as much as digits as its factorization.
421165411753 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 100800, while the sum is 40.
Adding to 421165411753 its reverse (357114561124), we get a palindrome (778279972877).
The spelling of 421165411753 in words is "four hundred twenty-one billion, one hundred sixty-five million, four hundred eleven thousand, seven hundred fifty-three".
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