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4213525305553 is a prime number
BaseRepresentation
bin111101010100001001101…
…011011101100011010001
3112220210211211020002122021
4331110021223131203101
51023013244434234203
612543400010211441
7613263041105614
oct75241153354321
915823754202567
104213525305553
111384a45209043
12580739123b81
13247445291995
14107d1584c17b
157490ba475bd
hex3d509add8d1

4213525305553 has 2 divisors, whose sum is σ = 4213525305554. Its totient is φ = 4213525305552.

The previous prime is 4213525305527. The next prime is 4213525305571. The reversal of 4213525305553 is 3555035253124.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3625493989329 + 588031316224 = 1904073^2 + 766832^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4213525305553 is a prime.

It is a super-3 number, since 3×42135253055533 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4213525303553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2106762652776 + 2106762652777.

It is an arithmetic number, because the mean of its divisors is an integer number (2106762652777).

Almost surely, 24213525305553 is an apocalyptic number.

It is an amenable number.

4213525305553 is a deficient number, since it is larger than the sum of its proper divisors (1).

4213525305553 is an equidigital number, since it uses as much as digits as its factorization.

4213525305553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350000, while the sum is 43.

The spelling of 4213525305553 in words is "four trillion, two hundred thirteen billion, five hundred twenty-five million, three hundred five thousand, five hundred fifty-three".