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42141050113 = 48463869551
BaseRepresentation
bin100111001111110011…
…010110010100000001
311000202212211011002211
4213033303112110001
51142301102100423
631205340542121
73021203005261
oct471763262401
9130685734084
1042141050113
1116965584748
128200b51941
133c87813c16
14207aaa17a1
15116995c10d
hex9cfcd6501

42141050113 has 4 divisors (see below), whose sum is σ = 42141968128. Its totient is φ = 42140132100.

The previous prime is 42141050059. The next prime is 42141050143. The reversal of 42141050113 is 31105014124.

42141050113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42141050113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (42141050143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386313 + ... + 483238.

It is an arithmetic number, because the mean of its divisors is an integer number (10535492032).

Almost surely, 242141050113 is an apocalyptic number.

It is an amenable number.

42141050113 is a deficient number, since it is larger than the sum of its proper divisors (918015).

42141050113 is an equidigital number, since it uses as much as digits as its factorization.

42141050113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 918014.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 42141050113 its reverse (31105014124), we get a palindrome (73246064237).

The spelling of 42141050113 in words is "forty-two billion, one hundred forty-one million, fifty thousand, one hundred thirteen".

Divisors: 1 48463 869551 42141050113