Base | Representation |
---|---|
bin | 111101010101101001011… |
… | …110000010011000101011 |
3 | 112220221222211020220121020 |
4 | 331111221132002120223 |
5 | 1023030042343233042 |
6 | 12544223255543523 |
7 | 613350624141645 |
oct | 75255136023053 |
9 | 15827884226536 |
10 | 4215132399147 |
11 | 138569a39526a |
12 | 580b0738aba3 |
13 | 24764020c437 |
14 | 10802906b895 |
15 | 749a2b983ec |
hex | 3d56978262b |
4215132399147 has 4 divisors (see below), whose sum is σ = 5620176532200. Its totient is φ = 2810088266096.
The previous prime is 4215132399091. The next prime is 4215132399151. The reversal of 4215132399147 is 7419932315124.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4215132399147 - 27 = 4215132399019 is a prime.
It is a super-3 number, since 3×42151323991473 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 4215132399147.
It is not an unprimeable number, because it can be changed into a prime (4215132399197) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 702522066522 + ... + 702522066527.
It is an arithmetic number, because the mean of its divisors is an integer number (1405044133050).
Almost surely, 24215132399147 is an apocalyptic number.
4215132399147 is a deficient number, since it is larger than the sum of its proper divisors (1405044133053).
4215132399147 is a wasteful number, since it uses less digits than its factorization.
4215132399147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1405044133052.
The product of its digits is 1632960, while the sum is 51.
The spelling of 4215132399147 in words is "four trillion, two hundred fifteen billion, one hundred thirty-two million, three hundred ninety-nine thousand, one hundred forty-seven".
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