Base | Representation |
---|---|
bin | 111101011101010001101… |
… | …110100100000111001001 |
3 | 112221202010201020000021221 |
4 | 331131101232210013021 |
5 | 1023143331421404001 |
6 | 12552100202402041 |
7 | 614060622541042 |
oct | 75352156440711 |
9 | 15852121200257 |
10 | 4223324013001 |
11 | 1389113337a75 |
12 | 582612800321 |
13 | 248347361722 |
14 | 1085a4d738c9 |
15 | 74cd1de31a1 |
hex | 3d751ba41c9 |
4223324013001 has 4 divisors (see below), whose sum is σ = 4223403806992. Its totient is φ = 4223244219012.
The previous prime is 4223324012983. The next prime is 4223324013017. The reversal of 4223324013001 is 1003104233224.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4223324013001 - 235 = 4188964274633 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4223324016001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39817551 + ... + 39923476.
It is an arithmetic number, because the mean of its divisors is an integer number (1055850951748).
Almost surely, 24223324013001 is an apocalyptic number.
It is an amenable number.
4223324013001 is a deficient number, since it is larger than the sum of its proper divisors (79793991).
4223324013001 is an equidigital number, since it uses as much as digits as its factorization.
4223324013001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79793990.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 4223324013001 its reverse (1003104233224), we get a palindrome (5226428246225).
The spelling of 4223324013001 in words is "four trillion, two hundred twenty-three billion, three hundred twenty-four million, thirteen thousand, one".
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