Base | Representation |
---|---|
bin | 10011001101011011111101… |
… | …10000111011110110101011 |
3 | 12112120101220100222022201021 |
4 | 21212231332300323312223 |
5 | 21014102412302112301 |
6 | 225502120455233311 |
7 | 11616652100314561 |
oct | 1146557660736653 |
9 | 175511810868637 |
10 | 42243130113451 |
11 | 12507235744713 |
12 | 48a3002978837 |
13 | 1a75682840097 |
14 | a6081520da31 |
15 | 4d3c9284b8a1 |
hex | 266b7ec3bdab |
42243130113451 has 2 divisors, whose sum is σ = 42243130113452. Its totient is φ = 42243130113450.
The previous prime is 42243130113403. The next prime is 42243130113479. The reversal of 42243130113451 is 15431103134224.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42243130113451 - 213 = 42243130105259 is a prime.
It is a super-2 number, since 2×422431301134512 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (42243130111451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21121565056725 + 21121565056726.
It is an arithmetic number, because the mean of its divisors is an integer number (21121565056726).
Almost surely, 242243130113451 is an apocalyptic number.
42243130113451 is a deficient number, since it is larger than the sum of its proper divisors (1).
42243130113451 is an equidigital number, since it uses as much as digits as its factorization.
42243130113451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 42243130113451 its reverse (15431103134224), we get a palindrome (57674233247675).
The spelling of 42243130113451 in words is "forty-two trillion, two hundred forty-three billion, one hundred thirty million, one hundred thirteen thousand, four hundred fifty-one".
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