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422441502001 is a prime number
BaseRepresentation
bin1100010010110110111…
…10011100010100110001
31111101101200012210100121
412021123132130110301
523410130011031001
6522022243250241
742343331343361
oct6113336342461
91441350183317
10422441502001
1115317a23aa72
1269a56979981
1330ab3aa2ccc
141663682c9a1
15aec6b876a1
hex625b79c531

422441502001 has 2 divisors, whose sum is σ = 422441502002. Its totient is φ = 422441502000.

The previous prime is 422441501983. The next prime is 422441502103. The reversal of 422441502001 is 100205144224.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 264657773601 + 157783728400 = 514449^2 + 397220^2 .

It is a cyclic number.

It is not a de Polignac number, because 422441502001 - 223 = 422433113393 is a prime.

It is a super-3 number, since 3×4224415020013 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (422441502401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211220751000 + 211220751001.

It is an arithmetic number, because the mean of its divisors is an integer number (211220751001).

Almost surely, 2422441502001 is an apocalyptic number.

It is an amenable number.

422441502001 is a deficient number, since it is larger than the sum of its proper divisors (1).

422441502001 is an equidigital number, since it uses as much as digits as its factorization.

422441502001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2560, while the sum is 25.

Adding to 422441502001 its reverse (100205144224), we get a palindrome (522646646225).

The spelling of 422441502001 in words is "four hundred twenty-two billion, four hundred forty-one million, five hundred two thousand, one".