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42244211131 = 68161619771
BaseRepresentation
bin100111010101111100…
…111000000110111011
311001001001221021102021
4213111330320012323
51143004004224011
631223504015311
73023564604253
oct472574700673
9131031837367
1042244211131
1116a08835091
12822b601537
133ca2cc3445
14208a676963
151173a38471
hex9d5f381bb

42244211131 has 4 divisors (see below), whose sum is σ = 42244899064. Its totient is φ = 42243523200.

The previous prime is 42244211129. The next prime is 42244211137. The reversal of 42244211131 is 13111244224.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 42244211131 - 21 = 42244211129 is a prime.

It is a super-2 number, since 2×422442111312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 42244211096 and 42244211105.

It is not an unprimeable number, because it can be changed into a prime (42244211137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241725 + ... + 378046.

It is an arithmetic number, because the mean of its divisors is an integer number (10561224766).

Almost surely, 242244211131 is an apocalyptic number.

42244211131 is a deficient number, since it is larger than the sum of its proper divisors (687933).

42244211131 is an equidigital number, since it uses as much as digits as its factorization.

42244211131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 687932.

The product of its digits is 1536, while the sum is 25.

Adding to 42244211131 its reverse (13111244224), we get a palindrome (55355455355).

The spelling of 42244211131 in words is "forty-two billion, two hundred forty-four million, two hundred eleven thousand, one hundred thirty-one".

Divisors: 1 68161 619771 42244211131