Base | Representation |
---|---|
bin | 10011001101101001101100… |
… | …01010100000000111011011 |
3 | 12112121002221010111122022211 |
4 | 21212310312022200013123 |
5 | 21014213012003412103 |
6 | 225505340200455551 |
7 | 11620332553402345 |
oct | 1146646612400733 |
9 | 175532833448284 |
10 | 42250502013403 |
11 | 1250a378a11212 |
12 | 48a451b77a5b7 |
13 | 1a76288bc9368 |
14 | a60d142d8295 |
15 | 4d4074b2836d |
hex | 266d362a01db |
42250502013403 has 8 divisors (see below), whose sum is σ = 43880795458560. Its totient is φ = 40650681343080.
The previous prime is 42250502013389. The next prime is 42250502013479. The reversal of 42250502013403 is 30431020505224.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 42250502013403 - 25 = 42250502013371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (42250502013103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7618190883 + ... + 7618196428.
It is an arithmetic number, because the mean of its divisors is an integer number (5485099432320).
Almost surely, 242250502013403 is an apocalyptic number.
42250502013403 is a deficient number, since it is larger than the sum of its proper divisors (1630293445157).
42250502013403 is a wasteful number, since it uses less digits than its factorization.
42250502013403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15236387417.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 42250502013403 its reverse (30431020505224), we get a palindrome (72681522518627).
The spelling of 42250502013403 in words is "forty-two trillion, two hundred fifty billion, five hundred two million, thirteen thousand, four hundred three".
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