Base | Representation |
---|---|
bin | 10011001101110010010100… |
… | …01000111101100100111011 |
3 | 12112121112212210212111110022 |
4 | 21212321022020331210323 |
5 | 21014302002310341103 |
6 | 225511423440041055 |
7 | 11620555364563445 |
oct | 1146711210754473 |
9 | 175545783774408 |
10 | 42255132121403 |
11 | 12511334547953 |
12 | 48a53b230318b |
13 | 1a76846228836 |
14 | a612331d1495 |
15 | 4d4246367138 |
hex | 266e4a23d93b |
42255132121403 has 4 divisors (see below), whose sum is σ = 42255145937928. Its totient is φ = 42255118304880.
The previous prime is 42255132121343. The next prime is 42255132121409. The reversal of 42255132121403 is 30412123155224.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 42255132121403 - 26 = 42255132121339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (42255132121409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53738 + ... + 9193103.
It is an arithmetic number, because the mean of its divisors is an integer number (10563786484482).
Almost surely, 242255132121403 is an apocalyptic number.
42255132121403 is a deficient number, since it is larger than the sum of its proper divisors (13816525).
42255132121403 is an equidigital number, since it uses as much as digits as its factorization.
42255132121403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13816524.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 42255132121403 its reverse (30412123155224), we get a palindrome (72667255276627).
The spelling of 42255132121403 in words is "forty-two trillion, two hundred fifty-five billion, one hundred thirty-two million, one hundred twenty-one thousand, four hundred three".
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