Base | Representation |
---|---|
bin | 10011001111011110111010… |
… | …01001111011101000110001 |
3 | 12112211010100220122012211002 |
4 | 21213233131021323220301 |
5 | 21021230402344414301 |
6 | 225554304534331345 |
7 | 11625021214564151 |
oct | 1147573511735061 |
9 | 175733326565732 |
10 | 42313433201201 |
11 | 12534031a2a028 |
12 | 48b47631b9b55 |
13 | 1a7c1a79c6aa6 |
14 | a63da41a0761 |
15 | 4d5a0987b16b |
hex | 267bdd27ba31 |
42313433201201 has 2 divisors, whose sum is σ = 42313433201202. Its totient is φ = 42313433201200.
The previous prime is 42313433201173. The next prime is 42313433201231. The reversal of 42313433201201 is 10210233431324.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41170201792801 + 1143231408400 = 6416401^2 + 1069220^2 .
It is a cyclic number.
It is not a de Polignac number, because 42313433201201 - 210 = 42313433200177 is a prime.
It is not a weakly prime, because it can be changed into another prime (42313433201231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21156716600600 + 21156716600601.
It is an arithmetic number, because the mean of its divisors is an integer number (21156716600601).
Almost surely, 242313433201201 is an apocalyptic number.
It is an amenable number.
42313433201201 is a deficient number, since it is larger than the sum of its proper divisors (1).
42313433201201 is an equidigital number, since it uses as much as digits as its factorization.
42313433201201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 42313433201201 its reverse (10210233431324), we get a palindrome (52523666632525).
The spelling of 42313433201201 in words is "forty-two trillion, three hundred thirteen billion, four hundred thirty-three million, two hundred one thousand, two hundred one".
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