Base | Representation |
---|---|
bin | 111101100110011010111… |
… | …011100110111111000001 |
3 | 112222200110221200201011221 |
4 | 331212122323212333001 |
5 | 1023323433334312001 |
6 | 13000402330235041 |
7 | 614556131124046 |
oct | 75463273467701 |
9 | 15880427621157 |
10 | 4233142104001 |
11 | 13922a13a6068 |
12 | 5844b2885a81 |
13 | 24925045a125 |
14 | 108c56ca31cd |
15 | 751a8d1c1a1 |
hex | 3d99aee6fc1 |
4233142104001 has 2 divisors, whose sum is σ = 4233142104002. Its totient is φ = 4233142104000.
The previous prime is 4233142103891. The next prime is 4233142104067. The reversal of 4233142104001 is 1004012413324.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3586766303376 + 646375800625 = 1893876^2 + 803975^2 .
It is a cyclic number.
It is not a de Polignac number, because 4233142104001 - 217 = 4233141972929 is a prime.
It is not a weakly prime, because it can be changed into another prime (4233142104601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116571052000 + 2116571052001.
It is an arithmetic number, because the mean of its divisors is an integer number (2116571052001).
Almost surely, 24233142104001 is an apocalyptic number.
It is an amenable number.
4233142104001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4233142104001 is an equidigital number, since it uses as much as digits as its factorization.
4233142104001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4233142104001 its reverse (1004012413324), we get a palindrome (5237154517325).
The spelling of 4233142104001 in words is "four trillion, two hundred thirty-three billion, one hundred forty-two million, one hundred four thousand, one".
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