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42333104131 = 94111449821
BaseRepresentation
bin100111011011001111…
…111110100000000011
311001021021012111200121
4213123033332200003
51143144233313011
631240401201111
73026024306443
oct473317764003
9131237174617
1042333104131
1116a53a2a77a
128255330197
133cb8548556
1420983b6123
15117b746e71
hex9db3fe803

42333104131 has 4 divisors (see below), whose sum is σ = 42333648064. Its totient is φ = 42332560200.

The previous prime is 42333104129. The next prime is 42333104137. The reversal of 42333104131 is 13140133324.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 42333104131 - 21 = 42333104129 is a prime.

It is a super-2 number, since 2×423331041312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 42333104096 and 42333104105.

It is not an unprimeable number, because it can be changed into a prime (42333104137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130800 + ... + 319021.

It is an arithmetic number, because the mean of its divisors is an integer number (10583412016).

Almost surely, 242333104131 is an apocalyptic number.

42333104131 is a deficient number, since it is larger than the sum of its proper divisors (543933).

42333104131 is an equidigital number, since it uses as much as digits as its factorization.

42333104131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 543932.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 42333104131 its reverse (13140133324), we get a palindrome (55473237455).

The spelling of 42333104131 in words is "forty-two billion, three hundred thirty-three million, one hundred four thousand, one hundred thirty-one".

Divisors: 1 94111 449821 42333104131