Base | Representation |
---|---|
bin | 111101100110101100010… |
… | …001110000000111011001 |
3 | 112222201020020021220210020 |
4 | 331212230101300013121 |
5 | 1023330032334334431 |
6 | 13000451243541053 |
7 | 614566263541602 |
oct | 75465421600731 |
9 | 15881206256706 |
10 | 4233433121241 |
11 | 13924306a4685 |
12 | 58457422a789 |
13 | 24929883138c |
14 | 108c837b8da9 |
15 | 751c4654696 |
hex | 3d9ac4701d9 |
4233433121241 has 8 divisors (see below), whose sum is σ = 5941660521120. Its totient is φ = 2673747234432.
The previous prime is 4233433121233. The next prime is 4233433121243. The reversal of 4233433121241 is 1421213343324.
4233433121241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4233433121241 - 23 = 4233433121233 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4233433121243) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37135378200 + ... + 37135378313.
It is an arithmetic number, because the mean of its divisors is an integer number (742707565140).
Almost surely, 24233433121241 is an apocalyptic number.
It is an amenable number.
4233433121241 is a deficient number, since it is larger than the sum of its proper divisors (1708227399879).
4233433121241 is a wasteful number, since it uses less digits than its factorization.
4233433121241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74270756535.
The product of its digits is 41472, while the sum is 33.
Adding to 4233433121241 its reverse (1421213343324), we get a palindrome (5654646464565).
The spelling of 4233433121241 in words is "four trillion, two hundred thirty-three billion, four hundred thirty-three million, one hundred twenty-one thousand, two hundred forty-one".
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