Base | Representation |
---|---|
bin | 111101100111001110110… |
… | …010011001000111011011 |
3 | 112222202201120202020121221 |
4 | 331213032302121013123 |
5 | 1023332224044300011 |
6 | 13001024525312511 |
7 | 614616524031466 |
oct | 75471662310733 |
9 | 15882646666557 |
10 | 4234012103131 |
11 | 13926a84a7308 |
12 | 5846b6105737 |
13 | 24935b77b305 |
14 | 108cda6502dd |
15 | 7520a3be971 |
hex | 3d9cec991db |
4234012103131 has 2 divisors, whose sum is σ = 4234012103132. Its totient is φ = 4234012103130.
The previous prime is 4234012103119. The next prime is 4234012103141. The reversal of 4234012103131 is 1313012104324.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4234012103131 - 25 = 4234012103099 is a prime.
It is a super-2 number, since 2×42340121031312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4234012103096 and 4234012103105.
It is not a weakly prime, because it can be changed into another prime (4234012103141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2117006051565 + 2117006051566.
It is an arithmetic number, because the mean of its divisors is an integer number (2117006051566).
Almost surely, 24234012103131 is an apocalyptic number.
4234012103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4234012103131 is an equidigital number, since it uses as much as digits as its factorization.
4234012103131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4234012103131 its reverse (1313012104324), we get a palindrome (5547024207455).
The spelling of 4234012103131 in words is "four trillion, two hundred thirty-four billion, twelve million, one hundred three thousand, one hundred thirty-one".
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