4234133000401 has 4 divisors (see below), whose sum is σ = 4234180262400. Its totient is φ = 4234085738404.

The previous prime is 4234133000291. The next prime is 4234133000417. The reversal of 4234133000401 is 1040003314324.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4234133000401 - 2¹⁵ = 4234132967633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4234133004401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23496361 + ... + 23675878.

It is an arithmetic number, because the mean of its divisors is an integer number (1058545065600).

Almost surely, 2^{4234133000401} is an apocalyptic number.

It is an amenable number.

4234133000401 is a deficient number, since it is larger than the sum of its proper divisors (47261999).

4234133000401 is an equidigital number, since it uses as much as digits as its factorization.

4234133000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47261998.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 4234133000401 its reverse (1040003314324), we get a palindrome (5274136314725).

The spelling of 4234133000401 in words is "four trillion, two hundred thirty-four billion, one hundred thirty-three million, four hundred one", and thus it is an aban number.