Base | Representation |
---|---|
bin | 111101101111111010110… |
… | …010110101001101101001 |
3 | 120000122210200111022010022 |
4 | 331233322302311031221 |
5 | 1024010330112202223 |
6 | 13005210314130225 |
7 | 615366633600431 |
oct | 75577262651551 |
9 | 16018720438108 |
10 | 4243340350313 |
11 | 13966550054a9 |
12 | 58647a120975 |
13 | 24a1b72395bc |
14 | 1095434ad2c1 |
15 | 755a42d9ac8 |
hex | 3dbfacb5369 |
4243340350313 has 2 divisors, whose sum is σ = 4243340350314. Its totient is φ = 4243340350312.
The previous prime is 4243340350303. The next prime is 4243340350393. The reversal of 4243340350313 is 3130530433424.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3325177779049 + 918162571264 = 1823507^2 + 958208^2 .
It is a cyclic number.
It is not a de Polignac number, because 4243340350313 - 24 = 4243340350297 is a prime.
It is not a weakly prime, because it can be changed into another prime (4243340350303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2121670175156 + 2121670175157.
It is an arithmetic number, because the mean of its divisors is an integer number (2121670175157).
Almost surely, 24243340350313 is an apocalyptic number.
It is an amenable number.
4243340350313 is a deficient number, since it is larger than the sum of its proper divisors (1).
4243340350313 is an equidigital number, since it uses as much as digits as its factorization.
4243340350313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 35.
Adding to 4243340350313 its reverse (3130530433424), we get a palindrome (7373870783737).
The spelling of 4243340350313 in words is "four trillion, two hundred forty-three billion, three hundred forty million, three hundred fifty thousand, three hundred thirteen".
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