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42444131412433 is a prime number
BaseRepresentation
bin10011010011010010010110…
…11000000010100111010001
312120021121201111101021012011
421221221023120002213101
521030401040120144213
6230134321554502521
711640326100212602
oct1151511330024721
9176247644337164
1042444131412433
1112584500736633
124915b59894a41
131a8b60643275a
14a6a442299da9
154d9108b5c03d
hex269a4b6029d1

42444131412433 has 2 divisors, whose sum is σ = 42444131412434. Its totient is φ = 42444131412432.

The previous prime is 42444131412359. The next prime is 42444131412479. The reversal of 42444131412433 is 33421413144424.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38802533972224 + 3641597440209 = 6229168^2 + 1908297^2 .

It is a cyclic number.

It is not a de Polignac number, because 42444131412433 - 233 = 42435541477841 is a prime.

It is a super-3 number, since 3×424441314124333 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (42444131412493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21222065706216 + 21222065706217.

It is an arithmetic number, because the mean of its divisors is an integer number (21222065706217).

Almost surely, 242444131412433 is an apocalyptic number.

It is an amenable number.

42444131412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

42444131412433 is an equidigital number, since it uses as much as digits as its factorization.

42444131412433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 442368, while the sum is 40.

Adding to 42444131412433 its reverse (33421413144424), we get a palindrome (75865544556857).

The spelling of 42444131412433 in words is "forty-two trillion, four hundred forty-four billion, one hundred thirty-one million, four hundred twelve thousand, four hundred thirty-three".