Base | Representation |
---|---|
bin | 110000010100010011111010… |
… | …1001010111101011011000011 |
3 | 2001201210222122100101011200112 |
4 | 1200220213311022331123003 |
5 | 421201231204101211120 |
6 | 4103524051531341535 |
7 | 155343345422202350 |
oct | 14050476512753303 |
9 | 2051728570334615 |
10 | 425004012132035 |
11 | 11346820a020396 |
12 | 3b80075b8b18ab |
13 | 1531b924ba456b |
14 | 76d443803d627 |
15 | 34204e2a55bc5 |
hex | 18289f52bd6c3 |
425004012132035 has 32 divisors (see below), whose sum is σ = 589224375277440. Its totient is φ = 288254057951232.
The previous prime is 425004012131969. The next prime is 425004012132041. The reversal of 425004012132035 is 530231210400524.
It is a cyclic number.
It is not a de Polignac number, because 425004012132035 - 218 = 425004011869891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 425004012131992 and 425004012132010.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31836824 + ... + 43169333.
It is an arithmetic number, because the mean of its divisors is an integer number (18413261727420).
Almost surely, 2425004012132035 is an apocalyptic number.
425004012132035 is a deficient number, since it is larger than the sum of its proper divisors (164220363145405).
425004012132035 is a wasteful number, since it uses less digits than its factorization.
425004012132035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75007935.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 425004012132035 its reverse (530231210400524), we get a palindrome (955235222532559).
The spelling of 425004012132035 in words is "four hundred twenty-five trillion, four billion, twelve million, one hundred thirty-two thousand, thirty-five".
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