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4252203864913 is a prime number
BaseRepresentation
bin111101111000001011000…
…110011101001101010001
3120001111200101202111100211
4331320023012131031101
51024132003142134123
613013234022044121
7616132401330034
oct75701306351521
916044611674324
104252203864913
11139a393255184
12588132579641
1324ac9a6401b4
14109b4471701b
157592250640d
hex3de0b19d351

4252203864913 has 2 divisors, whose sum is σ = 4252203864914. Its totient is φ = 4252203864912.

The previous prime is 4252203864901. The next prime is 4252203864917. The reversal of 4252203864913 is 3194683022524.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4012361535744 + 239842329169 = 2003088^2 + 489737^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4252203864913 is a prime.

It is a super-3 number, since 3×42522038649133 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4252203864917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2126101932456 + 2126101932457.

It is an arithmetic number, because the mean of its divisors is an integer number (2126101932457).

Almost surely, 24252203864913 is an apocalyptic number.

It is an amenable number.

4252203864913 is a deficient number, since it is larger than the sum of its proper divisors (1).

4252203864913 is an equidigital number, since it uses as much as digits as its factorization.

4252203864913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2488320, while the sum is 49.

The spelling of 4252203864913 in words is "four trillion, two hundred fifty-two billion, two hundred three million, eight hundred sixty-four thousand, nine hundred thirteen".