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425451023113 = 3311285350523
BaseRepresentation
bin1100011000011101101…
…10110110101100001001
31111200011102011022012111
412030032312312230021
523432310430214423
6523241031542321
742511034012404
oct6141666665411
91450142138174
10425451023113
111544840137a6
126a55682a9a1
133117343c12c
14168403d2d3b
15b100eac60d
hex630edb6b09

425451023113 has 4 divisors (see below), whose sum is σ = 426736373968. Its totient is φ = 424165672260.

The previous prime is 425451023099. The next prime is 425451023119. The reversal of 425451023113 is 311320154524.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-425451023113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (425451023119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642674931 + ... + 642675592.

It is an arithmetic number, because the mean of its divisors is an integer number (106684093492).

Almost surely, 2425451023113 is an apocalyptic number.

It is an amenable number.

425451023113 is a deficient number, since it is larger than the sum of its proper divisors (1285350855).

425451023113 is a wasteful number, since it uses less digits than its factorization.

425451023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1285350854.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 425451023113 its reverse (311320154524), we get a palindrome (736771177637).

The spelling of 425451023113 in words is "four hundred twenty-five billion, four hundred fifty-one million, twenty-three thousand, one hundred thirteen".

Divisors: 1 331 1285350523 425451023113