4255365401347 has 2 divisors, whose sum is σ = 4255365401348. Its totient is φ = 4255365401346.

The previous prime is 4255365401327. The next prime is 4255365401389. The reversal of 4255365401347 is 7431045635524.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4255365401347 is a prime.

It is a super-2 number, since 2×4255365401347² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4255365401347.

It is not a weakly prime, because it can be changed into another prime (4255365401327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2127682700673 + 2127682700674.

It is an arithmetic number, because the mean of its divisors is an integer number (2127682700674).

Almost surely, 2^{4255365401347} is an apocalyptic number.

4255365401347 is a deficient number, since it is larger than the sum of its proper divisors (1).

4255365401347 is an equidigital number, since it uses as much as digits as its factorization.

4255365401347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048000, while the sum is 49.

The spelling of 4255365401347 in words is "four trillion, two hundred fifty-five billion, three hundred sixty-five million, four hundred one thousand, three hundred forty-seven".