Base | Representation |
---|---|
bin | 10011011000110111101010… |
… | …00000100101111111000011 |
3 | 12120221221212002002121112002 |
4 | 21230123311000211333003 |
5 | 21042021414211003403 |
6 | 230402404320254215 |
7 | 11660226510003635 |
oct | 1154336500457703 |
9 | 176857762077462 |
10 | 42635955953603 |
11 | 12648897689591 |
12 | 494717347136b |
13 | 1aa3726a6790c |
14 | a7583c67ca55 |
15 | 4de0d44c8188 |
hex | 26c6f5025fc3 |
42635955953603 has 2 divisors, whose sum is σ = 42635955953604. Its totient is φ = 42635955953602.
The previous prime is 42635955953489. The next prime is 42635955953627. The reversal of 42635955953603 is 30635955953624.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42635955953603 - 216 = 42635955888067 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 42635955953603.
It is not a weakly prime, because it can be changed into another prime (42635955953653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21317977976801 + 21317977976802.
It is an arithmetic number, because the mean of its divisors is an integer number (21317977976802).
Almost surely, 242635955953603 is an apocalyptic number.
42635955953603 is a deficient number, since it is larger than the sum of its proper divisors (1).
42635955953603 is an equidigital number, since it uses as much as digits as its factorization.
42635955953603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 393660000, while the sum is 65.
The spelling of 42635955953603 in words is "forty-two trillion, six hundred thirty-five billion, nine hundred fifty-five million, nine hundred fifty-three thousand, six hundred three".
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