Base | Representation |
---|---|
bin | 111110000011011110101… |
… | …011011100111011001011 |
3 | 120002200000102121100200002 |
4 | 332003132223130323023 |
5 | 1024331333413142001 |
6 | 13023002400233215 |
7 | 620042256413525 |
oct | 76033653347313 |
9 | 16080012540602 |
10 | 4264343490251 |
11 | 13a4552802399 |
12 | 58a56000b80b |
13 | 24c1836b0660 |
14 | 10a576abca15 |
15 | 75dd315746b |
hex | 3e0deadcecb |
4264343490251 has 16 divisors (see below), whose sum is σ = 4705134473088. Its totient is φ = 3839692569600.
The previous prime is 4264343490229. The next prime is 4264343490293. The reversal of 4264343490251 is 1520943434624.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4264343490251 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4264343490196 and 4264343490205.
It is not an unprimeable number, because it can be changed into a prime (4264343490151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2695646 + ... + 3974316.
It is an arithmetic number, because the mean of its divisors is an integer number (294070904568).
Almost surely, 24264343490251 is an apocalyptic number.
4264343490251 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
4264343490251 is a deficient number, since it is larger than the sum of its proper divisors (440790982837).
4264343490251 is a wasteful number, since it uses less digits than its factorization.
4264343490251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1284982.
The product of its (nonzero) digits is 2488320, while the sum is 47.
The spelling of 4264343490251 in words is "four trillion, two hundred sixty-four billion, three hundred forty-three million, four hundred ninety thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •