Base | Representation |
---|---|
bin | 111110000100001101010… |
… | …001111010010101010001 |
3 | 120002202000220202122002210 |
4 | 332010031101322111101 |
5 | 1024334434040332423 |
6 | 13023212125502333 |
7 | 620100532036533 |
oct | 76041521722521 |
9 | 16082026678083 |
10 | 4265125324113 |
11 | 13a4914065785 |
12 | 58a739a119a9 |
13 | 24c279672a44 |
14 | 10a60c879853 |
15 | 75e2bae1b93 |
hex | 3e10d47a551 |
4265125324113 has 4 divisors (see below), whose sum is σ = 5686833765488. Its totient is φ = 2843416882740.
The previous prime is 4265125324081. The next prime is 4265125324127. The reversal of 4265125324113 is 3114235215624.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 4265125324113 - 25 = 4265125324081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4265125324153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710854220683 + ... + 710854220688.
It is an arithmetic number, because the mean of its divisors is an integer number (1421708441372).
Almost surely, 24265125324113 is an apocalyptic number.
It is an amenable number.
4265125324113 is a deficient number, since it is larger than the sum of its proper divisors (1421708441375).
4265125324113 is a wasteful number, since it uses less digits than its factorization.
4265125324113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1421708441374.
The product of its digits is 172800, while the sum is 39.
The spelling of 4265125324113 in words is "four trillion, two hundred sixty-five billion, one hundred twenty-five million, three hundred twenty-four thousand, one hundred thirteen".
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