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42693202537 is a prime number
BaseRepresentation
bin100111110000101101…
…101001001001101001
311002012100210101211121
4213300231221021221
51144413424440122
631340223255241
73040656143146
oct476055511151
9132170711747
1042693202537
1117119221a67
128335a4a521
13404502902b
1420d01513cd
15119d177bc7
hex9f0b69269

42693202537 has 2 divisors, whose sum is σ = 42693202538. Its totient is φ = 42693202536.

The previous prime is 42693202499. The next prime is 42693202547. The reversal of 42693202537 is 73520239624.

42693202537 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42690171456 + 3031081 = 206616^2 + 1741^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42693202537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 42693202493 and 42693202502.

It is not a weakly prime, because it can be changed into another prime (42693202547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21346601268 + 21346601269.

It is an arithmetic number, because the mean of its divisors is an integer number (21346601269).

Almost surely, 242693202537 is an apocalyptic number.

It is an amenable number.

42693202537 is a deficient number, since it is larger than the sum of its proper divisors (1).

42693202537 is an equidigital number, since it uses as much as digits as its factorization.

42693202537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 42693202537 in words is "forty-two billion, six hundred ninety-three million, two hundred two thousand, five hundred thirty-seven".