Base | Representation |
---|---|
bin | 10011011110000111001100… |
… | …00001011011100100111011 |
3 | 12121121011211010222212220211 |
4 | 21233003212001123210323 |
5 | 21102444324321010212 |
6 | 231021235221331551 |
7 | 12006234462562123 |
oct | 1157034601334473 |
9 | 177534733885824 |
10 | 42816093141307 |
11 | 12708226401932 |
12 | 4976066b66bb7 |
13 | 1ab7703c43405 |
14 | a8044a789c83 |
15 | 4e3b28c7e9a7 |
hex | 26f0e605b93b |
42816093141307 has 2 divisors, whose sum is σ = 42816093141308. Its totient is φ = 42816093141306.
The previous prime is 42816093141149. The next prime is 42816093141379. The reversal of 42816093141307 is 70314139061824.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42816093141307 - 243 = 34020000119099 is a prime.
It is not a weakly prime, because it can be changed into another prime (42816093145307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21408046570653 + 21408046570654.
It is an arithmetic number, because the mean of its divisors is an integer number (21408046570654).
Almost surely, 242816093141307 is an apocalyptic number.
42816093141307 is a deficient number, since it is larger than the sum of its proper divisors (1).
42816093141307 is an equidigital number, since it uses as much as digits as its factorization.
42816093141307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 49.
The spelling of 42816093141307 in words is "forty-two trillion, eight hundred sixteen billion, ninety-three million, one hundred forty-one thousand, three hundred seven".
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