Base | Representation |
---|---|
bin | 10011011110010110010100… |
… | …11100101100110000110011 |
3 | 12121121221210112222120011012 |
4 | 21233023022130230300303 |
5 | 21103113000414242011 |
6 | 231025101510141135 |
7 | 12006643050634043 |
oct | 1157131234546063 |
9 | 177557715876135 |
10 | 42824220462131 |
11 | 127107170312a9 |
12 | 49777549517ab |
13 | 1ab83ca9746a4 |
14 | a809bbd17723 |
15 | 4e3e52529a8b |
hex | 26f2ca72cc33 |
42824220462131 has 2 divisors, whose sum is σ = 42824220462132. Its totient is φ = 42824220462130.
The previous prime is 42824220462013. The next prime is 42824220462161. The reversal of 42824220462131 is 13126402242824.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42824220462131 - 230 = 42823146720307 is a prime.
It is a super-2 number, since 2×428242204621312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (42824220462161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21412110231065 + 21412110231066.
It is an arithmetic number, because the mean of its divisors is an integer number (21412110231066).
Almost surely, 242824220462131 is an apocalyptic number.
42824220462131 is a deficient number, since it is larger than the sum of its proper divisors (1).
42824220462131 is an equidigital number, since it uses as much as digits as its factorization.
42824220462131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 294912, while the sum is 41.
The spelling of 42824220462131 in words is "forty-two trillion, eight hundred twenty-four billion, two hundred twenty million, four hundred sixty-two thousand, one hundred thirty-one".
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