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430044111422041 is a prime number
BaseRepresentation
bin110000111000111110111001…
…0011111111100001001011001
32002101122211000112101021212211
41201301331302133330021121
5422331320320011001131
64122343312031035121
7156403442656252534
oct14161756237741131
92071584015337784
10430044111422041
11115030757741a46
124029551a96baa1
13155c5ca777365c
14782a36323ba1b
1534ab67a8235b1
hex1871f727fc259

430044111422041 has 2 divisors, whose sum is σ = 430044111422042. Its totient is φ = 430044111422040.

The previous prime is 430044111421987. The next prime is 430044111422087. The reversal of 430044111422041 is 140224111440034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 329194394001225 + 100849717420816 = 18143715^2 + 10042396^2 .

It is a cyclic number.

It is not a de Polignac number, because 430044111422041 - 225 = 430044077867609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 430044111421994 and 430044111422012.

It is not a weakly prime, because it can be changed into another prime (430044111422141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215022055711020 + 215022055711021.

It is an arithmetic number, because the mean of its divisors is an integer number (215022055711021).

Almost surely, 2430044111422041 is an apocalyptic number.

It is an amenable number.

430044111422041 is a deficient number, since it is larger than the sum of its proper divisors (1).

430044111422041 is an equidigital number, since it uses as much as digits as its factorization.

430044111422041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 430044111422041 its reverse (140224111440034), we get a palindrome (570268222862075).

The spelling of 430044111422041 in words is "four hundred thirty trillion, forty-four billion, one hundred eleven million, four hundred twenty-two thousand, forty-one".