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430100020131 = 32112832400929
BaseRepresentation
bin1100100001000111111…
…01010111101110100011
31112010011102001211012020
412100203331113232203
524021321101121011
6525330224032523
743034164564515
oct6204375275643
91463142054166
10430100020131
1115644a280aa1
126b433762743
1331734653142
1416b61a05bb5
15b2c41cd006
hex6423f57ba3

430100020131 has 16 divisors (see below), whose sum is σ = 578220773760. Its totient is φ = 284365912320.

The previous prime is 430100020123. The next prime is 430100020151. The reversal of 430100020131 is 131020001034.

It is not a de Polignac number, because 430100020131 - 23 = 430100020123 is a prime.

It is a super-2 number, since 2×4301000201312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 430100020131.

It is not an unprimeable number, because it can be changed into a prime (430100020121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1021326 + ... + 1379603.

It is an arithmetic number, because the mean of its divisors is an integer number (36138798360).

Almost surely, 2430100020131 is an apocalyptic number.

430100020131 is a deficient number, since it is larger than the sum of its proper divisors (148120753629).

430100020131 is a wasteful number, since it uses less digits than its factorization.

430100020131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2401426.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 430100020131 its reverse (131020001034), we get a palindrome (561120021165).

The spelling of 430100020131 in words is "four hundred thirty billion, one hundred million, twenty thousand, one hundred thirty-one".

Divisors: 1 3 211 283 633 849 59713 179139 2400929 7202787 506596019 679462907 1519788057 2038388721 143366673377 430100020131