Base | Representation |
---|---|
bin | 10011100011110000101111… |
… | …10101101001010110011001 |
3 | 12122021201211221212222212222 |
4 | 21301320113311221112121 |
5 | 21114134343311103423 |
6 | 231250340401313425 |
7 | 12026245624445105 |
oct | 1161702765512631 |
9 | 178251757788788 |
10 | 43010202441113 |
11 | 12782585005866 |
12 | 49a77b9935875 |
13 | 1accac9a1526b |
14 | a899c2390905 |
15 | 4e8bd9eab3c8 |
hex | 271e17d69599 |
43010202441113 has 4 divisors (see below), whose sum is σ = 43011597141120. Its totient is φ = 43008807741108.
The previous prime is 43010202441097. The next prime is 43010202441121. The reversal of 43010202441113 is 31114420201034.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 43010202441113 - 24 = 43010202441097 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (43010202449113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 697303745 + ... + 697365422.
It is an arithmetic number, because the mean of its divisors is an integer number (10752899285280).
Almost surely, 243010202441113 is an apocalyptic number.
It is an amenable number.
43010202441113 is a deficient number, since it is larger than the sum of its proper divisors (1394700007).
43010202441113 is a wasteful number, since it uses less digits than its factorization.
43010202441113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1394700006.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 43010202441113 its reverse (31114420201034), we get a palindrome (74124622642147).
The spelling of 43010202441113 in words is "forty-three trillion, ten billion, two hundred two million, four hundred forty-one thousand, one hundred thirteen".
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