Base | Representation |
---|---|
bin | 111110100101101101100… |
… | …111110101111001011101 |
3 | 120020011220011010212122221 |
4 | 332211231213311321131 |
5 | 1030432123431033341 |
6 | 13051522042305341 |
7 | 622513205613010 |
oct | 76455547657135 |
9 | 16204804125587 |
10 | 4301101424221 |
11 | 14090a5696218 |
12 | 5956ba1b8251 |
13 | 252790b86344 |
14 | 10c262871377 |
15 | 76d351d1ed1 |
hex | 3e96d9f5e5d |
4301101424221 has 16 divisors (see below), whose sum is σ = 4982386679424. Its totient is φ = 3636662768064.
The previous prime is 4301101424219. The next prime is 4301101424237. The reversal of 4301101424221 is 1224241011034.
It is a cyclic number.
It is not a de Polignac number, because 4301101424221 - 21 = 4301101424219 is a prime.
It is a super-2 number, since 2×43011014242212 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4301101424281) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5289006 + ... + 6047791.
It is an arithmetic number, because the mean of its divisors is an integer number (311399167464).
Almost surely, 24301101424221 is an apocalyptic number.
It is an amenable number.
4301101424221 is a deficient number, since it is larger than the sum of its proper divisors (681285255203).
4301101424221 is a wasteful number, since it uses less digits than its factorization.
4301101424221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11337540.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4301101424221 its reverse (1224241011034), we get a palindrome (5525342435255).
The spelling of 4301101424221 in words is "four trillion, three hundred one billion, one hundred one million, four hundred twenty-four thousand, two hundred twenty-one".
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