Base | Representation |
---|---|
bin | 101000000011101010… |
… | …000001100101000001 |
3 | 11010000111211020222021 |
4 | 220003222001211001 |
5 | 1201041310133441 |
6 | 31431535241441 |
7 | 3051565435015 |
oct | 500352014501 |
9 | 133014736867 |
10 | 43011021121 |
11 | 17271666852 |
12 | 8404379281 |
13 | 4095b25373 |
14 | 2120442545 |
15 | 11bb0063d1 |
hex | a03a81941 |
43011021121 has 2 divisors, whose sum is σ = 43011021122. Its totient is φ = 43011021120.
The previous prime is 43011021101. The next prime is 43011021143. The reversal of 43011021121 is 12112011034.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27258010000 + 15753011121 = 165100^2 + 125511^2 .
It is a cyclic number.
It is not a de Polignac number, because 43011021121 - 219 = 43010496833 is a prime.
It is a super-2 number, since 2×430110211212 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43011021095 and 43011021104.
It is not a weakly prime, because it can be changed into another prime (43011021101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505510560 + 21505510561.
It is an arithmetic number, because the mean of its divisors is an integer number (21505510561).
Almost surely, 243011021121 is an apocalyptic number.
It is an amenable number.
43011021121 is a deficient number, since it is larger than the sum of its proper divisors (1).
43011021121 is an equidigital number, since it uses as much as digits as its factorization.
43011021121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 43011021121 its reverse (12112011034), we get a palindrome (55123032155).
The spelling of 43011021121 in words is "forty-three billion, eleven million, twenty-one thousand, one hundred twenty-one".
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