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43013035150121 is a prime number
BaseRepresentation
bin10011100011110110000001…
…01011100100101100101001
312122022000011101010112010102
421301323000223210230221
521114211143444300441
6231251525432155145
712026406052204001
oct1161730053445451
9178260141115112
1043013035150121
11127837a8aa3a93
1249a826a538ab5
131b0015b85553a
14a89bb068b001
154e8d03a0769b
hex271ec0ae4b29

43013035150121 has 2 divisors, whose sum is σ = 43013035150122. Its totient is φ = 43013035150120.

The previous prime is 43013035150051. The next prime is 43013035150139. The reversal of 43013035150121 is 12105153031034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41656555647721 + 1356479502400 = 6454189^2 + 1164680^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43013035150121 is a prime.

It is not a weakly prime, because it can be changed into another prime (43013035150021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506517575060 + 21506517575061.

It is an arithmetic number, because the mean of its divisors is an integer number (21506517575061).

Almost surely, 243013035150121 is an apocalyptic number.

It is an amenable number.

43013035150121 is a deficient number, since it is larger than the sum of its proper divisors (1).

43013035150121 is an equidigital number, since it uses as much as digits as its factorization.

43013035150121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 43013035150121 its reverse (12105153031034), we get a palindrome (55118188181155).

The spelling of 43013035150121 in words is "forty-three trillion, thirteen billion, thirty-five million, one hundred fifty thousand, one hundred twenty-one".