Base | Representation |
---|---|
bin | 111110100101111001101… |
… | …100110001011011101011 |
3 | 120020012102021101222201011 |
4 | 332211321230301123223 |
5 | 1030433032313340433 |
6 | 13051554121204351 |
7 | 622521216056014 |
oct | 76457154613353 |
9 | 16205367358634 |
10 | 4301304043243 |
11 | 1409199aa7959 |
12 | 5957560306b7 |
13 | 2527c3b4975c |
14 | 10c28173600b |
15 | 76d47da73cd |
hex | 3e979b316eb |
4301304043243 has 2 divisors, whose sum is σ = 4301304043244. Its totient is φ = 4301304043242.
The previous prime is 4301304043207. The next prime is 4301304043247. The reversal of 4301304043243 is 3423404031034.
4301304043243 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4301304043243 - 237 = 4163865089771 is a prime.
It is a super-2 number, since 2×43013040432432 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4301304043247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150652021621 + 2150652021622.
It is an arithmetic number, because the mean of its divisors is an integer number (2150652021622).
Almost surely, 24301304043243 is an apocalyptic number.
4301304043243 is a deficient number, since it is larger than the sum of its proper divisors (1).
4301304043243 is an equidigital number, since it uses as much as digits as its factorization.
4301304043243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 4301304043243 its reverse (3423404031034), we get a palindrome (7724708074277).
The spelling of 4301304043243 in words is "four trillion, three hundred one billion, three hundred four million, forty-three thousand, two hundred forty-three".
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