Base | Representation |
---|---|
bin | 111110100110000001010… |
… | …001100000010110101010 |
3 | 120020012202010111210211021 |
4 | 332212001101200112222 |
5 | 1030433312331110010 |
6 | 13052014500523054 |
7 | 622524321124114 |
oct | 76460121402652 |
9 | 16205663453737 |
10 | 4301431113130 |
11 | 14092547a8398 |
12 | 5957906b048a |
13 | 25281427a638 |
14 | 10c2945723b4 |
15 | 76d541078da |
hex | 3e9814605aa |
4301431113130 has 32 divisors (see below), whose sum is σ = 7746264016128. Its totient is φ = 1719753096000.
The previous prime is 4301431113101. The next prime is 4301431113131. The reversal of 4301431113130 is 313111341034.
It is a junction number, because it is equal to n+sod(n) for n = 4301431113095 and 4301431113104.
It is not an unprimeable number, because it can be changed into a prime (4301431113131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 344356185 + ... + 344368675.
It is an arithmetic number, because the mean of its divisors is an integer number (242070750504).
Almost surely, 24301431113130 is an apocalyptic number.
4301431113130 is a deficient number, since it is larger than the sum of its proper divisors (3444832902998).
4301431113130 is a wasteful number, since it uses less digits than its factorization.
4301431113130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26142.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 4301431113130 its reverse (313111341034), we get a palindrome (4614542454164).
The spelling of 4301431113130 in words is "four trillion, three hundred one billion, four hundred thirty-one million, one hundred thirteen thousand, one hundred thirty".
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