Base | Representation |
---|---|
bin | 111110100110100100100… |
… | …011111000010010010111 |
3 | 120020021021101111111110121 |
4 | 332212210203320102113 |
5 | 1030441020410213221 |
6 | 13052153325532411 |
7 | 622545100163422 |
oct | 76464443702227 |
9 | 16207241444417 |
10 | 4302023132311 |
11 | 14095289a5143 |
12 | 595916a14107 |
13 | 2528a9b10748 |
14 | 10c30d03c9b9 |
15 | 76d8b09aa41 |
hex | 3e9a48f8497 |
4302023132311 has 16 divisors (see below), whose sum is σ = 4462360616448. Its totient is φ = 4144645043200.
The previous prime is 4302023132293. The next prime is 4302023132359. The reversal of 4302023132311 is 1132313202034.
It is a cyclic number.
It is not a de Polignac number, because 4302023132311 - 229 = 4301486261399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4302023132111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 932110 + ... + 3077803.
It is an arithmetic number, because the mean of its divisors is an integer number (278897538528).
Almost surely, 24302023132311 is an apocalyptic number.
4302023132311 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
4302023132311 is a deficient number, since it is larger than the sum of its proper divisors (160337484137).
4302023132311 is a wasteful number, since it uses less digits than its factorization.
4302023132311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4010282.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 4302023132311 its reverse (1132313202034), we get a palindrome (5434336334345).
The spelling of 4302023132311 in words is "four trillion, three hundred two billion, twenty-three million, one hundred thirty-two thousand, three hundred eleven".
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