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4302130312033 is a prime number
BaseRepresentation
bin111110100110101010111…
…100101111001101100001
3120020021112212011210101221
4332212222330233031201
51030441230324441113
613052212115055041
7622550541200641
oct76465274571541
916207485153357
104302130312033
11140958344a924
125959468a1481
132528c60991b8
1410c31d37c521
1576d956bc98d
hex3e9aaf2f361

4302130312033 has 2 divisors, whose sum is σ = 4302130312034. Its totient is φ = 4302130312032.

The previous prime is 4302130312019. The next prime is 4302130312037. The reversal of 4302130312033 is 3302130312034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4260950538849 + 41179773184 = 2064207^2 + 202928^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4302130312033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4302130311989 and 4302130312007.

It is not a weakly prime, because it can be changed into another prime (4302130312037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2151065156016 + 2151065156017.

It is an arithmetic number, because the mean of its divisors is an integer number (2151065156017).

Almost surely, 24302130312033 is an apocalyptic number.

It is an amenable number.

4302130312033 is a deficient number, since it is larger than the sum of its proper divisors (1).

4302130312033 is an equidigital number, since it uses as much as digits as its factorization.

4302130312033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 4302130312033 its reverse (3302130312034), we get a palindrome (7604260624067).

Subtracting from 4302130312033 its reverse (3302130312034), we obtain a palindrome (999999999999).

The spelling of 4302130312033 in words is "four trillion, three hundred two billion, one hundred thirty million, three hundred twelve thousand, thirty-three".