Base | Representation |
---|---|
bin | 101000000100010011… |
… | …111111110110110001 |
3 | 11010001021112021020111 |
4 | 220010103333312301 |
5 | 1201102114232423 |
6 | 31433011141321 |
7 | 3052061112505 |
oct | 500423776661 |
9 | 133037467214 |
10 | 43022024113 |
11 | 172778a1532 |
12 | 8407ba4841 |
13 | 40981a8603 |
14 | 2121aa8305 |
15 | 11bbe7b60d |
hex | a044ffdb1 |
43022024113 has 2 divisors, whose sum is σ = 43022024114. Its totient is φ = 43022024112.
The previous prime is 43022024069. The next prime is 43022024119. The reversal of 43022024113 is 31142022034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42740187169 + 281836944 = 206737^2 + 16788^2 .
It is a cyclic number.
It is not a de Polignac number, because 43022024113 - 213 = 43022015921 is a prime.
It is a super-3 number, since 3×430220241133 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (43022024119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21511012056 + 21511012057.
It is an arithmetic number, because the mean of its divisors is an integer number (21511012057).
Almost surely, 243022024113 is an apocalyptic number.
It is an amenable number.
43022024113 is a deficient number, since it is larger than the sum of its proper divisors (1).
43022024113 is an equidigital number, since it uses as much as digits as its factorization.
43022024113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 43022024113 its reverse (31142022034), we get a palindrome (74164046147).
The spelling of 43022024113 in words is "forty-three billion, twenty-two million, twenty-four thousand, one hundred thirteen".
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